Resposta:
Zeros a # x = -2 # i # x = -3 #
Explicació:
# x ^ 2 + 5x = -6 #
#hArrcolor (blanc) ("XXX") x ^ x + 5x + 6 = 0 #
#hArrcolor (blanc) ("XXX") (x + 2) (x + 3) = 0
tampoc
#color (blanc) ("XXX") (x + 2) = 0color (blanc) ("XX") rarrcolor (blanc) ("XX") x = -2 #
o bé
#color (blanc) ("XXX") (x + 3) = 0color (blanc) ("XX") rarrcolor (blanc) ("XX") x = -3 #