Com solucioneu cos 2x + 3 sinx - 2 = 0?

Com solucioneu cos 2x + 3 sinx - 2 = 0?
Anonim

Resposta:

# S = {pi / 6 + 2pin, (5pi) / 6 + 2pin, x = pi / 2 + 2pin} #

Explicació:

Utilitza la propietat Double Argument:

# cos2A = 1-2sin ^ 2A #

# 1-2sin ^ 2x + 3sinx-2 = 0 #

# 2sin ^ 2x-3sinx + 1 = 0 #

# (2sinx-1) (sinx-1) = 0

# 2sinx-1 = 0 o sinx-1 = 0 #

# sinx = 1/2 o sinx = 1

# x = sin ^ -1 (1/2) o x = sin ^ -1 1 #

# x = pi / 6 + 2pin, (5pi) / 6 + 2pin o x = pi / 2 + 2pin

# S = {pi / 6 + 2pin, (5pi) / 6 + 2pin, x = pi / 2 + 2pin} #