Quina és la forma polar de (13,1)?

Quina és la forma polar de (13,1)?
Anonim

Resposta:

# (sqrt (170), tan ^ -1 (1/13)) - = (13.0,0.0768 ^ c) #

Explicació:

Per a un conjunt donat de coordenades # (x, y) #, # (x, y) -> (rcostheta, rsintheta) #

# r = sqrt (x ^ 2 + y ^ 2) #

# theta = tan ^ -1 (i / x) #

# r = sqrt (13 ^ 2 + 1 ^ 2) = sqrt (169 + 1) = sqrt (170) = 13,0 #

# theta = tan ^ -1 (1/13) = 0,0768 ^ c #

# (13,1) -> (sqrt (170), tan ^ -1 (1/13)) - = (13.0,0.0768 ^ c) #